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4y^2-15y-25=0
a = 4; b = -15; c = -25;
Δ = b2-4ac
Δ = -152-4·4·(-25)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-25}{2*4}=\frac{-10}{8} =-1+1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+25}{2*4}=\frac{40}{8} =5 $
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